Little-endian YDL?

[Norberto Quintanar]

Sorry couldn't resist
--- Robert Sanders <rarob@comcast.net> wrote:
> >On Nov 20, 2003, at 7:46 PM, Chris Gehlker wrote:
> >
> >
> >Example: on a LE processor, if you store the 32-bit number 
> >0x01020304 to address 0, memory looks like this:
> >
> >mem[0] = 0x04
> >mem[1] = 0x03
> >mem[2] = 0x02
> >mem[3] = 0x01
> >
> >On a PPC with the LE bit set, you get instead:
> >
> >mem[0] = (Not changed)
> >mem[1] = (Not changed)
> >mem[2] = (Not changed)
> >mem[3] = (Not changed)
> >mem[4] = 0x01
> >mem[5] = 0x02
> >mem[6] = 0x03
> >mem[7] = 0x04
> >
> >No, I'm not making this up.  Really.  Honest!  Look in the PPC
> spec 
> >for the full details if you don't believe me.  You probably will
> not 
> >believe such a horrible hack ever made it into a CPU architecture 
> >definition.  (In fact, you probably won't believe it actually
> works.)
> >
> 
> 
> Egads!  I think my 'yeesh' from a previous reply wasn't strong 
> enough.  So the PPC in LE mode is going to take
> a 32bit number, drop it into the space of a 64 bit (disregarding
> the 
> 'high' bits) in BE mode, *access* the bytes
> in reverse from the high end of the BE 64 bit space?!


A big-endian and a little-endian have been spotted sitting at a
campfire nibling on bytes and pointing at each other as they argued
about who got hit with the most errors. 


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