Re: Help: Kernel Patching for a 6400


Subject: Re: Help: Kernel Patching for a 6400
From: Brandon Murakami (bmurakami@ucdavis.edu)
Date: Tue May 23 2000 - 12:57:14 MDT


I followed the advice quoted below (thank you sa), although I used
version 0.9.43 instead of 0.9.41. Earlier, I couldn't get past a dry
run test of the kernel patching. With 0.9.43, now the patch can get
past the dry run stage and the several make stages. However, now I
can't find the kernel ("vmlinux") that the patch is supposed to
create. Here is exactly what I've done:

1. Formatted and reinstalled LinuxPPC 2000.
2. Downloaded and did a "rpm -U" on version 0.9.43.
3. Checked the patch on a dry run. No errors.
4. Performed the patch exactly as described in
/usr/doc/mol-0.9.43/Kernel_Patches/PATCHING.
5. Executed the following:

                 cd /usr/src/linux
                 make clean
                 make xconfig
                 make clean
                 make dep
                 make

The last step ("make") does not make the "vmlinux" kernel as the
PATCHING instructions say it should. After spitting a lot of stuff
on the screen, the last few lines it writes is:

make[2]: Leaving directory `/usr/src/linux-2.2.14/arch/ppc/mm'
make -C arch/ppc/lib fastdep
make[2]: Entering directory `/usr/src/linux-2.2.14/arch/ppc/lib'
/usr/src/linux/scripts/mkdep checksum.S locks.c strcase.c string.S > .depend
make[2]: Leaving directory `/usr/src/linux-2.2.14/arch/ppc/lib'
make[1]: Leaving directory `/usr/src/linux-2.2.14'

And then I get the bash prompt. I "ls" to check for a "vmlinux" file
and there is none. I searched in /usr/src/linux (like PATCHING says
to) and also /usr/src/linux-2.2.14. I don't see "vmlinux" anywhere.

Did my makes go wrong? I saw no errors. Is vmlinux hiding
somewhere? Please help if you can.

Brandon

>Hi, I believe there was a bug in older mols' patches, If you upgrade to
>mol-0.9.41, the patches should apply with no problem. If you still want
>to know what the - +'s are, just examine a patch, or read the patch man
>page It's pretty self explanitory.
>
>HTH,
>sa



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